(2t-3)^2-12(2t-3)+35=0

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Solution for (2t-3)^2-12(2t-3)+35=0 equation: 



(2t-3)^2-12(2t-3)+35=0

We multiply parentheses

(2t-3)^2-24t+36+35=0

We add all the numbers together, and all the variables

-24t+(2t-3)^2+71=0

We move all terms containing t to the left, all other terms to the right

-24t+(2t-3)^2=-71

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